Hello The Energy Needed For The Following Process Is 1 96 X 104 Kj Mol

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The energy needed for the following process is 1.96 x 104 kJ/mol:

Li (g) —-> Li+3 (g) + 3 e-

If the first ionization of lithium is 520 kJ/mol, calculate the second ionization of lithium, that is the energy required for the process:

Li+ (g) —-> Li+2 (g) + e-

(Hint: ???? = − 2.18 ∗ 10+,- ???? 01, where Z is the atomic number of the element of interest.) 


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